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irga5000 [103]
3 years ago
14

BRAINLIESTthrough: (-3,5) parallel to y=-2x-3

Mathematics
2 answers:
brilliants [131]3 years ago
6 0
Draw a table for y=-2x-3
drawn and plot a 4 quadrant graph
draw line y=-2x-3
cross off (-3,5)
draw a line that crosses through that point and is parallel to the other line
umka2103 [35]3 years ago
4 0

Answer:

Parallel Lines have the SAME SLOPE

We first Find the Slope of the line  

y = 2 x + 3

The Slope Intercept Form of the equation of a given line is:

y = m x + c

where  m  is the Slope of that line, and  c  is the Y intercept. For this line, the Slope is  2  So the Slope of the line PARALLEL to  

y = 2 x + 3

will also be  2 . And we are given that it passes through the point  

( − 3 , 4 )  

With this, we can use the Point Slope form to find the equation of the line.  

The Point-Slope form of the Equation of a Straight Line is:

( y − k ) = m ⋅ ( x − h )  m  is the Slope of the Line  

( h , k )  are the co-ordinates of any point on that Line.  

Here, we have been given the coordinates  

( h , k )  of 1 point on that line as  ( − 3 , 4 )  

And the Slope  m  is  2

Substituting the values of  h , k and m  in the Point-Slope form, we get

( y − 4 ) = ( 2) ⋅ ( x − ( − 3 ) )

The above will be the Equation of the Line in Point-Slope form.

If we need it in the Slope Intercept Form, we need to follow these steps:

Modifying the equation, we get:

( y − 4 ) = 2 ⋅ ( x + 3 )  

y − 4 = 2 x + 6

y = 2 x + 6 + 4  

We get the equation of the line as :

y = 2 x + 10

Step-by-step explanation:

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GuDViN [60]
An even function can be reflected about the y axis and map onto itself
example: y=x^2

an odd function can be reflected about the origin and map onto itself
example: y=x^3


a simple test is the following

if f(x) is even then f(-x)=f(x)
if f(x) is odd then f(-x)=-f(x)


so

even function
subsitute -x for each and see if we get the same function
remember to fully expand these

g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original one

g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
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not same because the original has -2x
not even


g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
same, it's even

g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
not the same, not even

g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
not same, not even



g(x)=2x²+1 is the even function
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<h3>Given that it is arithmetic</h3>

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Step-by-step explanation:

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