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Rzqust [24]
3 years ago
5

Wei has $150.00 to make a garland using 60-cent balloons. He wants to purchase 100 blue balloons and some number of white balloo

ns. He learns that the white balloons are on sale for half price. He writes and solves an equation to find the number of white balloons he can purchase.
Which models can be used to solve the problem?
a. 100b + w = 150; 6,000 + w = 150
b. 100b + w = 150; 100b + 30 = 150
c. 0.60b + 0.30w = 150; 60 + 0.30w = 150
d. 0.60b + 0.30w = 150; 100 + 0.30w = 150
answer is c
Mathematics
2 answers:
Ronch [10]3 years ago
5 0
Well he wants to buy 100 blue balloons so that would cost 100*0.6. The cost of white balloons(because they are half off) are w*0.3. He has a total of 150 dollars to we get 100*0.6+w*0.3=150 or 60+0.3w=150
Thus we get c
VikaD [51]3 years ago
4 0

This correct is c

O.6 0b + 0.30w= 150; 60 + 0.30W = 150

Update 8/3/18 ☑️

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Answer:

Se fabricaron:

1000 balones de los que cuestan $20

75 balones de los que cuestan $30

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Step-by-step explanation:

Vamos a definir las variables:

x = número de balones de $100.00 vendidos.

y = número de balones de $120.00 vendidos

z = número de balones de $160,00 vendidos.

Sabemos que se producen 1125 balones, entonces:

x + y + z = 1125

y el costo de producción es $24,250, conociendo el costo de cada balón podemos escribir:

x*$20 + y*$30 + z*$40 = $24,250

Y también sabemos que la ganancia mensual es $92,750

Ganancia es la diferencia entre el dinero total recibido y los costos, entonces:

x*$100 + y*$120 + z*$160 - $24,250 =  $92,750

x*$100 + y*$120 + z*$160 = $92,750 + $24,250

x*$100 + y*$120 + z*$160 = $117,000

Entonces tenemos un sistema de 3 ecuaciones:

x + y + z = 1125

x*$20 + y*$30 + z*$40 = $24,250

x*$100 + y*$120 + z*$160 = $117,000

Para resolver esto debemos comenzar por aislar alguna variable en alguna de las ecuaciones, yo comenzare aislando x en la primera ecuación:

x = 1125 - y - z

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(1125 - y - z)*$100 + y*$120 + z*$160 = $117,000

Si simplificamos esto obtenemos:

$22,500 + y*$10 + z*$20 = $24,250

$112,500 + y*$20 + z*$60 =  $117,000

Ahora de vuelta, debemos aislar una variable en una de las ecuaciones, si aislamos y en la primera ecuación obtenemos:

y*$10 = $24,250 - $22,500 -  z*$20

y = ($1,750 - z*$20)/$10

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Reemplazando esto en la otra ecuación obtenemos:

$112,500 + (175 - 2*z)*$20 + z*$60 =  $117,000

Ahora podemos resolver esto para z.

(175 - 2*z)*$20 + z*$60 =  $117,000 - $112,500

(175 - 2*z)*$20 + z*$60 = $4,500

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Usando la ecuación y = 175 - 2*z podemos encontrar el valor de y.

y = 175 - 2*50 = 75

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Usando la ecuación x = 1125 - y - z podemos encontrar el valor de x.

x = 1125 - 75 - 50 = 1000

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