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stellarik [79]
3 years ago
6

Find the slope of the line that passes through the pair of points. (if an answer is undefined, enter undefined.) (−a + 2, b − 3)

and (a + 2, −b)
Mathematics
1 answer:
inysia [295]3 years ago
3 0
M=(y2-y1)/(x2-x1)
 (x1,y1)=<span>(−a + 2, b − 3)
</span> (x2,y2)=<span>(a + 2, −b) 
 then, </span>substituting
 m=((-b)-(b − 3))/((a + 2)-(−a + 2))
 m=(-2b+3)/(2a)
 with
 a=/0
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Silva set up a dog-walking business. He earned $60 in June. He is projected to earn 110% more in July. How much is Silva project
MissTica

Answer:

$126

Step-by-step explanation:

just used the calculator

4 0
3 years ago
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Which of the ordered pairs is a solution to the system of inequalities? y &gt; 5 y ≥ x (0, 0) (4, 5) (-5, 4) (-5, 6)
yKpoI14uk [10]

Plug the y value in for y and plug the x value in for x

> less than

<u>></u> less than or equal to

Example:

(4,5)

y > 5y <u>></u> x

5 > 5x5 <u>></u> 4  =  5 > 25 <u>></u> 4  =  false

they all should be false

if one had to be correct, I would say (0, 0)

3 0
3 years ago
Please help me.
oksano4ka [1.4K]

Answer:

5 Soup can

Step-by-step explanation:

If 3 soup can cost $3.75

Then 1 soup can will cost $3.75/3

So, how many can soup will cost $6.25

= $6.26/(cost of 1 soup can)

= $6.25/($3.75/3)

=$6.25 × 3÷ 3.75

= 5 cans of soup

3 0
4 years ago
En las olimpiadas matemáticas,la hora de inicio del evento se expresa en una ecuación simple: 2x+6=x+17 ¿A qué hora empezó el ev
Sergio [31]

Answer:

11 minutos.

Step-by-step explanation:

En las Olimpiadas de Matemáticas, la hora de inicio del evento se expresa en una ecuación simple: 2x + 6 = x + 17 ¿A qué hora comenzó el evento?

La hora en que comienza el evento en los juegos olímpicos se representa como x

Por tanto: 2x + 6 = x + 17

Recopilar términos similares

2x - x = 17 - 6

x = 11 minutos

Por lo tanto, los eventos comienzan en 11 minutos.

7 0
3 years ago
Help please!
Mamont248 [21]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Sum & Difference Identity: cos (A + B) = cos A · cos B - sin A · sin B

Recall the following from Unit Circle: cos (π/2) = 0, sin (π/2) = 1

                                                              cos (π) = -1,   sin (π) = 0    

Use the Quotient Identity:   \tan A=\dfrac{\sin A}{\cos A}

<u>Proof LHS → RHS:</u>

\text{LHS:}\qquad \qquad \dfrac{\cos \bigg(\dfrac{\pi}{2}+x\bigg)}{\cos \bigg(\pi +x\bigg)}

\text{Sum Difference:}\qquad \dfrac{\cos \dfrac{\pi}{2}\cdot \cos x-\sin \dfrac{\pi}{2}\cdot \sin x}{\cos \pi \cdot \cos x-\sin \pi \cdot \sin x}

\text{Unit Circle:}\qquad \qquad \dfrac{0\cdot \cos x-1\cdot \sin x}{-1\cdot \cos x-0\cdot \sin x}

                            =\dfrac{-\sin x}{-\cos x}

Quotient:                 tan x

LHS = RHS \checkmark

7 0
3 years ago
Read 2 more answers
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