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4 years ago

15

An employee worked 160.5 hours in may, 165.75 hours in June and 152.25 hours in July.

1 answer:

Evgen [1.6K]4 years ago

5 0

160.5+165.75+152.25=474.5
474.5/3=(about) 158.1667
He worked an average of about 158.1667 hours each month.

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1 (9x+2)=4+ 2 (6x+4)<br> 3 3

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Answer:i think

Step-by-step explanation:

1(9x+2)=4+2(6x+4)33

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=9 * 396 x x+2 * 396 x+9 * 268 x+2 * 268

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Determine whether or not the following relations represents a function. Use a mapping diagram for each relation to help you solv

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Determine a constant in 9x + 4y -13.<br> A) -13<br> B) 9x<br> C) 4y

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3 years ago

A car travels at a rate of 50 miles per hour for 3 hours. Let y be the distance, in miles, the car travels for a given amount of

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3 years ago

Ava wants to draw a parallelogram on the coordinate plane. She

wolverine [178]

Answer:

$k =(2,1)$

$JK = 2$

Step-by-step explanation:

Given

$J = (0,1)$ ---- $(x_1,y_1)$

$H = (1,-2)$ --- $(x_2,y_2)$

$I = (3,-2)$ --- $(x_3,y_3)$

See attachment for grid

Solving (a): The coordinates of K

The parallelogram has the following diagonals: IJ and HK

Diagonals bisect one another. So:

Midpoint of IJ = Midpoint of HK

This gives:

$\frac{1}{2}(I + J) = \frac{1}{2}(H+K)$

$\frac{1}{2}(x_3+x_1,y_3+y_1) = \frac{1}{2}(x_2+x,y_2+y)$

$\frac{1}{2}(3+0,-2+1) = \frac{1}{2}(1+x,-2+y)$

$\frac{1}{2}(3,-1) = \frac{1}{2}(1+x,-2+y)$

Multiply through by 2

$(3,-1) = (1+x,-2+y)$

By comparison:

$1 + x = 3$

$-2 + y = -1$

Solve for x and y

$x = 3 - 1 =2$

$y = -1 +2 = 1$

So, the coordinates of k is:

$k =(2,1)$

The length of JK is calculated using distance (d) formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

$J = (0,1)$ ---- $(x_1,y_1)$

$k =(2,1)$ ---- $(x_2,y_2)$

So:

$d = \sqrt{(0 - 2)^2 + (1 - 1)^2$

$d = \sqrt{(- 2)^2 + (0)^2$

$d = \sqrt{4 + 0$

$d = \sqrt{4$

$d = 2$

Hence:

$JK = 2$

8 0

3 years ago