The unknowns in this problem are A. The number of boys and the number of girls in the class.
We know there are 7 more girls than boys, but because we don't know how many boys there are, we don't know how many girls there are.
Hope this helps you good luck
For the answer to the question above,
the answer is "<span>The student can have only one blood type, so the actual events are mutually exclusive. "</span>
<span>The probabilities are not mutually exclusive. Based on the group </span>
<span>P(Type O) = 9/20 = 45% or 0.45 </span>
<span>P(Type A) = 2/5 = 40% or 0.40 </span>
<span>P(Other) = 3/20 = 15% or 0.15
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
To solve this problem, we must simplify the the equation:
<span>Here is the base equation -2m - 5m - 8 = 3 + (-7) + m (Add all like terms):
</span>#1 -2m - 5m - 8 = 3 + (-7) + m (Property of Addition)<span>
#2 -7m - 8 = -4 + m (Most Simplified Equation)
The answer your would be the 2nd one. </span>-7m - 8 = m - 4
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