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4 years ago

The sum of two numbers is 64. One number is 8 more than the other. What are the two numbers?

Mathematics

1 answer:

lisabon 2012 [21]4 years ago

4 0

Answer:

28 and 36.

Step-by-step explanation:

Alright, so we are given that the sum of two numbers is 64. Based on this, we know that we are going to be adding because the question said "the sum of two numbers is 64." Sum is the answer to an addition problem. Lets write an equation.

We need a variable, let x be the variable which is the value of the smaller number.

the equation is x+x+8=64

x= to the smaller number

x+8= to the number that is eight more than x or the smaller number.

Before we isolate for x, we need to simplify the expression by combining the like terms.

x plus x equals 2x.

Therefore, we have 2x+8=64.

Our goal is to isolate x, so we need to subtract 8 from both sides. 8 mius 8 is 0, and 64 mius 8 is 56.

Now, we have 2x=56.

We still need to isolate x by dividing both sides by 2. 2 divided by 2 is 1, so we are left with 1x or x. 56 divided by 2 is 28.

x=28.

Great, we found what x or the smaller value is.

Now, we need to find the larger number.

Substitute x as 28 into x+8 to find the number that is 8 more than the smaller number or x. You'll then get 36. If you add 36 and 28, you get 64. Also, 36 is 8 more than 28, so this answer is correct.

Hope this helps!

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Answer:

Step-by-step explanation:

Hello!

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Sample 1 (aqueous film forming foam)

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S₁= 0.6

Sample 2 (alcohol-type concentrates )

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X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= $\frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }$

a) 95% CI

(X[bar]_1 - X[bar]_2) ± $t_{n_1 + n_2 - 2}$ * $Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }$

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Sa= 0.707ç

$t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306$

(4.7-6.9) ± 2.306* $(0.707\sqrt{\frac{1}{5}+\frac{1}{5} })$

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

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The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

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3 years ago

BRAINLIEST FOR BEST ANSWER

Temka [501]

Answer:

Option C is correct

The coordinate of C' or the transformed point of C is (-6, 5)

Step-by-step explanation:

From the given graph:

In triangle ABC:

Coordinate of C is:

C(-3, 4)

The rule of transformation is given:

$(x, y) \rightarrow (x-3, y+1)$

We have to find the coordinate of C'.

Apply the transformation on coordinate C:

$C(-3, 4) \rightarrow C'(-3-3, 4+1) = C'(-6, 5)$

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3 years ago

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From the first equation:

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