Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
b
Step-by-step explanation:
i did it
X+12 is the answer to your question
Use trigonometry:-
sin 26.5 = y / 15 (as sin = adj / hyp)
y = 15 sin 26.5 = 6.69 feet to nearest hundredth
This is more of a common sense problem rather than actual math.
Since we are trying to see the distribution of scores, it is not very practical to use 1 point. 15 and 20 point distributions are a bit big. Thus, the answer is 5 (most histograms in math class do use 5 for their scale).