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4 years ago

Does the rule y = –3x^5 represent an exponential function? ...?

1 answer:

7 0

Exponential function is <span>a function whose value is a constant raised to the power of the argument, especially the function where the constant is </span>e<span>. The function given y=-3x^5 cannot be considered as an exponential function. Instead, it is a polynomial function with a degree of 5. Hope this answers the question.</span>

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2 parts red with 3 parts cream and 1 part blue how much cream and blue will you need to mix with 4 litres of red

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4 red 6 cream 3 blue

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3 years ago

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FrozenT [24]

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Use the information given to enter an equation in standard form.

Greeley [361]

Answer:

y = -2x + 25

Step-by-step explanation:

A standard equation can be in slope-intercept form: y = mx + b

m is the slope, b is the y-intercept.

Plug in the given slope.

y = -2x + b

To find b, plug in the given point (9, 7).

7 = -2(9) + b

Multiply.

7 = -18 + b

Add 18 to both sides to find b.

25 = b

Plug this into your standard equation.

y = -2x + 25

Check by plugging in the given point again.

7 = -2(9) + 25

7 = -18 + 25

7 = 7

Your answer is correct!

Hope this helps!

3 0

3 years ago

Let V be the volume of a right circular cone of height h=14 whose base is a circle of radius R=2. An illustration a right circul

Alla [95]

Answer:

The area of a horizontal cross section at a height is $\pi\times(2-\dfrac{y}{7})^2$

Step-by-step explanation:

Given that,

Height = 14 m

Radius = 2 m

Let V be the volume of a right circular cone

We need to calculate the value of R

Using given data

$\dfrac{h}{r}=\dfrac{h-y}{R}$

Put the value into the formula

$\dfrac{14}{2}=\dfrac{14-y}{R}$

$7R=14-y$

$R=2-\dfrac{y}{7}$

We need to calculate the area of a horizontal cross section at a height y

Using formula of area

$A=\pi R^2$

Put the value into the formula

$A=\pi\times(2-\dfrac{y}{7})^2$

Hence, The area of a horizontal cross section at a height is $\pi\times(2-\dfrac{y}{7})^2$

3 0

3 years ago

How long will it take for $2500 to double if it is invested at 6% annual interest compounded 6 times a year? Enter exact calcula

12345 [234]

Answer:

Part 1) $t=11.610\ years$

Part 2) $t=11.552\ years$

Step-by-step explanation:

Part 1) we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06\\n=6$

substitute in the formula above

$5,000=2,500(1+\frac{0.06}{6})^{6t}$

$2=(1.01)^{6t}$

Apply log both sides

$log(2)=log[(1.01)^{6t}]$

$log(2)=(6t)log(1.01)$

solve for t

$t=log(2)/[6log(1.01)]$

$t=11.610\ years$

Part 2) we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06$

substitute in the formula above

$5,000=2,500(e)^{0.06t}$

$2=(e)^{0.06t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.06t}]$

$ln(2)=(0.06t)ln(e)$

$ln(2)=(0.06t)$

$t=ln(2)/(0.06)$

$t=11.552\ years$

3 0

3 years ago