Complete question :
The diameter of the ferris Given is 63 feets
Answer:
3165 feets
Step-by-step explanation:
Given that :
Diameter of ferris = 63 feets
Recall :
Circumference of a circle = 2 * pi * Radius
Or
Circumference = pi * d
Hence,
Circumference of wheel = 3.14 * 63 = 197.82 feets
Distance traveled during one ride :
Circumference of wheel * number of revolutions
197.82 * 16 = 3165.12
= 3165 feets (nearest whole number)
Answer:
50%
Step-by-step explanation:
3450 - 2300 = 1150
1150/ 2300 × 100 = 50
Answer: Surface area is equal to 200
Volume is equal to 333.33
Step-by-step explanation:
First, let's do surface area.
The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base
The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.
The lateral height is given as 5 cm.
The area of the base is 10(10) = 100.
We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200
.
Now for volume.
The volume of a pyramid is equal to 1/3(area of the base)(height).
We already have the area of the base, which is 100.
The height is given as 10 cm.
Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33
.
Hope this helps!
916...the 9 is in the hundreds place so its value is 900
791...the 9 is in the tens place so its value is 90
900/90 = 10
so the 9 in 916 is 10 times bigger then the 9 in 791
We know for our problem that Rachel makes $10 per hour. Since

represent the number of hours that she works,

will be the total amount that she will make for working

hours. We also know that she sells bracelets for $5 each. Since

represents the number of of bracelets that she sells,

will be her total revenue for selling

bracelets. We also know that she needs to earn at least $200 a week to cover her expenses, so the sum of

and

must be equal or greater than 200:

We can conclude that <span>the graphs that shows the inequality that represents this situation, with its solution region shaded is:</span>