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Georgia [21]
4 years ago
15

What are the domain and range of g(x)=−14(x−21)2+47?

Mathematics
1 answer:
Taya2010 [7]4 years ago
4 0

Answer:

Step-by-step explanation:

Let's solve for g.

gx=(−14(x−21))(2)+47

Step 1: Divide both sides by x.

gx

x

=

−28x+635

x

g=

−28x+635

x

Answer:

g=

−28x+635

x

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Let f(x)=x^2−2bx, where b is a constant. What can you say about the zeros, y-intercept, axis of symmetry and extreme value of f(
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