Answer:
Part A) ![27.78\ min](https://tex.z-dn.net/?f=27.78%5C%20min)
Part B) ![32.22\ min](https://tex.z-dn.net/?f=32.22%5C%20min)
Step-by-step explanation:
Part A)
Let
----> length song ![1](https://tex.z-dn.net/?f=1)
----> length song ![2](https://tex.z-dn.net/?f=2)
----> length song ![3](https://tex.z-dn.net/?f=3)
----> length song ![4](https://tex.z-dn.net/?f=4)
----> length song ![5](https://tex.z-dn.net/?f=5)
-----> break between each song
we know that
The length of the CD is equal to
![(t1+t2+t3+t4+t5)+4(b)](https://tex.z-dn.net/?f=%28t1%2Bt2%2Bt3%2Bt4%2Bt5%29%2B4%28b%29)
substitute the values
![(6.5+8+3.93+4.1+5.05)+4(0.05)=27.58+0.20=27.78\ min](https://tex.z-dn.net/?f=%286.5%2B8%2B3.93%2B4.1%2B5.05%29%2B4%280.05%29%3D27.58%2B0.20%3D27.78%5C%20min)
Part B)
Subtract the total length of the CD from
minutes of music
so
![(60-27.78)=32.22\ min](https://tex.z-dn.net/?f=%2860-27.78%29%3D32.22%5C%20min)
Answer:
0
Step-by-step explanation:
D = 20²-4(5)(20) = 400-400 = 0
M=cost per movie
v=cost per video game
2m+5v=33
8m+3v=30
use elimination
eliminate movies
mutliply first equation by -4 and add to 2nd
first equation becomes -8m-20v=-132
add the 2 equations
-8m-20v=-132
<u>8m+3v=30 +</u>
0m-17v=-102
-17v=-102
divide both sides by -17
v=6
subsiutute back
2m+5v=33
2m+5(6)=33
2m+30=33
minus 30 both sides
2m=3
divide 2
m=1.5
rental cost per movie is $1.50
rental cost per video game is $6
<span>791.28 I believe..................</span>