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horrorfan [7]
3 years ago
15

Find the volume of the pyramid below. Hint: The base is a right triangle, so you will need to find

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0

<u>Given</u>:

Given that the height of the pyramid is 12 units.

The base of the triangle is 8 units.

The height of the triangle is 6 units.

We need to determine the volume of the pyramid.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

A=\frac{1}{2} bh

where b is the base of the triangle and h is the height of the triangle.

Substituting the values, we get;

A=\frac{1}{2}(8)(6)

A=\frac{1}{2}(48)

A=24

Thus, the area of the triangle is 24 square units.

<u>Volume of the pyramid:</u>

The volume of the pyramid can be determined using the formula,

V=\frac{1}{3}AH

where A is the area of the triangle and H is the height of the pyramid.

Substituting the values, we get;

V=\frac{1}{3}(24)(12)

V=\frac{1}{3}(288)

V=96

Thus, the volume of the pyramid is 96 cubic units.

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The conjugate of (2+i)²/3+i, in the form of a+ib, is
goblinko [34]

Given that

(2+i)²/(3+i)

On multiplying both numerator and the denominator with (3-i) then

⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]

⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]

⇛ [(2+i)²(3-i)]/[(3²-i²)

⇛ [(2+i)²(3-i)]/(9-i²)

⇛ [(2+i)²(3-i)]/[9-(-1)]

Since ,i² = -1

⇛ [(2+i)²(3-i)]/(9+1)

⇛ [(2+i)²(3-i)]/10

⇛ [{2²+i²+2(2)(i)}(3-i)]/10

⇛ (4+i²+4i)(3-i)/10

⇛ (4-1+4i)(3-i)/10

⇛ (3+4i)(3-i)/10

⇛ (9-3i+12i-4i²)/10

⇛ (9+9i-4(-1))/10

Since, i² = -1

⇛(9+9i+4)/10

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⇛ (13/10)+ i (9/10)

We know that

The conjugate of a+ib is a-ib

So,

The conjugate of (13/10)+ i (9/10) is

(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)

<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)

<em>Additional</em><em> comment</em><em>:</em>

  • The conjugate of a+ib is a-ib and
  • i = -1
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