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Galina-37 [17]
3 years ago
10

Help plz!! i am having a hard time

Mathematics
1 answer:
beks73 [17]3 years ago
8 0
If x represents the number of flower baskets, then, just as you showed, the answer cant be either a or b because store A doesnt charge $15 per flower basket but rather $15 for delivery. To see whether it is c or d, simply use the same number to represent the number of flower baskets in both inequalities. The easiest would be 1 because then youre multiplying - in the case of store A - 19.25 (how much each flower basket costs) times 1 (the total number of flower baskets) and then adding 15 (the cost of delivery) which is a total of 34.25. For store B it would be 17.5 times 1 plus 30 which equals 47.5. Therefore, the inequality for store A is less than that of store B, so D would be the answer. (i hope that sort of makes sense sjdjdjjs)
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For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
Hector is competing in a 42 mile bicycle race, he has already completed 18 miles of the race ad is traveling at a constant speed
kkurt [141]
Time it took Hector to complete 18 miles is given by 18 / 12 = 1.5 hours.

Let the time when Wanda will catch up to Hector be t, then, the distance covered by Hector at the time they meet is 18 + 12t and the distance covered by Wanda at the time they meet is 16t.

Then, 18 + 12t = 16t
16t - 12t = 18
4t = 18
t = 18 / 4 = 4.5

Therefore, Wanda will catch up with Hector after 4.5 hours.
7 0
3 years ago
Write a direct variation equation that relates x
8_murik_8 [283]

Answer:

y/x= -8/-2= 4 => when y=32 => 32/x=4 => x=8

4 0
2 years ago
for what values of A does the acute angle formed by the lines 3x+2y=10 and Ax-2y=3 have measure of 45 degree
Nonamiya [84]

Answer:

Step-by-step explanation:

8 0
2 years ago
Bob and James are finishing the roof of a house. Working alone, Bob can shingle the roof in 14 hours. James can shingle the same
Snowcat [4.5K]

we know that Bob can do the whole job in 14 hours, how much of the work has he done in 1 hour only?  well since he can do the whole lot in 14 hours in 1 hour he has only done 1/14 th of the job.

we know that James can do it in 18 hours, a bit slower, so in 1 hour he has done only 1/18 th of the job.

let's say it takes both of them working together say "t" hours, so in 1 hour Bob has done (1/14) of the work whilst James has done (1/18) of the work, the whole work being t/t or 1 whole, so for just one hour that'd 1/t done by both Bob and James.

\bf \stackrel{Bob}{\cfrac{1}{14}}~~+~~\stackrel{James}{\cfrac{1}{18}}~~=~~\stackrel{total~for~1~hour}{\cfrac{1}{t}} \\\\\\ \stackrel{\textit{using an LCD of 126}}{\cfrac{9+7}{126}=\cfrac{1}{t}}\implies \cfrac{16}{126}=\cfrac{1}{t}\implies 16t=126\implies t=\cfrac{126}{16} \\\\\\ \stackrel{\textit{7 hrs, 52 minutes and 30 seconds}}{t=\cfrac{63}{8}\implies t=7\frac{7}{8}}\implies \stackrel{\textit{rounded up}}{t=7.88}

7 0
3 years ago
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