1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuki888 [10]
3 years ago
10

Invent a five-value data set for which the mean is 6 and the mode is not 6

Mathematics
1 answer:
GaryK [48]3 years ago
3 0
Mean is the average
mode is most common number
we can do
hmm
average of 3 and 9 is 6

3,3,6,9,9 will work
we can make it vary slightly
2,4,6,9,9
mean is 6, mode is 9
You might be interested in
Two sides of an isosceles triangle measure 3 inches and 7 inches. Which could be the length of the third side?
MrRa [10]
7? An isosceles triangle has two indentical sides(you can remember that by saying you have TWO eyes hint EYEsosceles) but I’m guessing the bottom is 3 and the two sides are 7?
8 0
3 years ago
Each unit on the grid represents 5
ollegr [7]

Answer:

There's no grid but I'd say A if you can give me the grid I'll edit my answer

Step-by-step explanation:

7 0
3 years ago
In△XYZ , XY¯¯¯¯¯¯=7in , YZ¯¯¯¯¯=5in , and XZ¯¯¯¯¯=4in . This triangle is reflected across the x-axis to result in △X'Y'Z' . Whic
ki77a [65]

Answer:

B

Step-by-step explanation:

Reflection is a transformation that preserves lengths.

Triangle XYZ, with side lengths XY = 7 in, YZ = 5 in, XZ = 4 in, is reflected across the x-axis to result in △X'Y'Z'.

This means that corresponding sides have the same lengths:

  • XY = X'Y' = 7 in;
  • XZ = X'Z' = 4 in;
  • YZ = Y'Z' = 5 in.

Find the perimeters of both triangles:

P_{XYZ}=XY+XZ+YZ=7+4+5=16\ in\\ \\P_{X'Y'Z'}=X'Y'+X'Z'+Y'Z'=7+4+5=16\ in

Hence, only option B is true.

8 0
3 years ago
(x2 + 10x + 21) - (x + 7)
rusak2 [61]

Answer:

11x+14

Step-by-step explanation:

(2x+10x+21)-x-7 = 12x+21-x-7 = 11x+14

3 0
3 years ago
A cylinder has a height of 8.1 inches and circular base with a diameter of 2.7 inches. The cylinder contains 3 green spheres, ea
klasskru [66]

Answer:

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

Step-by-step explanation:

Let's find volume of the cylinder and volume of the three spheres.

Volume of cylinder =\pi r^{2} h

Volume of sphere =\frac{4}{3} \pi r^{3}

Now, r =2.7

h=8.1

Find volume of each shape.

Volume of cylinder =\pi (2.7)^{2} (8.1)

                             =59.049\pi

Now, volume of 3 spheres =3*\frac{4}{3} *\pi *(2.7)^{3}

                                         =78.732\pi

Now, p(E)=\frac{Outcomes favorable to event E}{Total number of outcomes}

So, Probability of point is chosen at random inside the cylinder which belongs outside of the spheres  is

                  \frac{78.732\pi -59.049\pi }{78.732\pi }

Let's simplify them

             0.25

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

6 0
3 years ago
Other questions:
  • What is 0.83 ÷ 0.415 show ur work <br><br><br> help me pls
    9·2 answers
  • Maria has 180 pieces of chocolate candy and 144 pieces of fruity candy. She wants to give each child the same amount of candy so
    10·1 answer
  • Which of the following is the same as 8.4 × 10 to the 2nd power
    12·1 answer
  • Need help with number 13 plz :D
    10·1 answer
  • there are 5 more crows than cows in a farm field. there is a total of 52 legs on all the animals. How many crows and how many co
    8·1 answer
  • X-3&lt;-12 Choose the correct graph for the inequality?
    15·1 answer
  • Find the slope of the line graphed below
    10·2 answers
  • Withdrew $130.47 from an ATM on Tuesday. Wednesday he deposited $240.93. Friday he wrote a check for $56.02. What was the total
    6·2 answers
  • Solve 3x−5 = 9. <br> x = −3 <br> x = 2 <br> x = 7 <br> x = 8
    10·2 answers
  • Can someone help me with this?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!