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geniusboy [140]
3 years ago
9

Which statement is true of every plane in three-dimensional space?

Mathematics
2 answers:
olga55 [171]3 years ago
7 0
<span>Every plane must have three intercepts.

proof, every  point P in a </span><span>plane in three-dimensional space is written as  P=(x, y, z), x, y and z are intercepts.

</span>
leonid [27]3 years ago
4 0

Answer:

option A is correct.(Every plane must have three intercepts.)

Step-by-step explanation:

" Three-dimensional space (also: 3-space or, rarely, tri-dimensional space) is a geometric setting in which three values (called parameters) are required to determine the position of an element (i.e., point). This is the informal meaning of the term dimension "

The intercept form of the equation of plane in 3-D is given by:

\dfrac{x}{l}+\dfrac{y}{m}+\dfrac{z}{n}=1

Where l,m,n are intercepts of x,y,z axes and a plane respectively.

Hence, we require all the three intercepts of a every plane.

Hence, option A is correct.

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Please help on two math questions. I don’t understand how to do them.
Sidana [21]

When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.

In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be

x\leq -2 \lor\ x>1

or, in interval notation,

(-\infty,-2]\cup (1,\infty)

In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.

This means that the difference between your numbers at 1 must be at most 4, which is modelled by

|x-1|\leq 4

where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.

3 0
3 years ago
Given circle B, with a radius AB of 10 inches and a central angle ABC of 75º , find the length of the arc AC.
andre [41]
13.1 inches is the answer
7 0
3 years ago
How do you solve: secx=-5/2, tanx&lt;0<br><br> Find all six trig functions
Brut [27]

Answer:

sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21

Step-by-step explanation:

During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.

5 0
3 years ago
Help me pleas please can i get help
givi [52]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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nignag [31]

Answer:

Step-by-step explanation:

x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \beta \beta \alpha \neq \geq \\ \left \{ {{y=2} \atop {x=2}} \right.

3 0
3 years ago
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