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3 years ago

Please help i will mark you brainest plz Name the congruent triangles in the diagram.Explain.

Mathematics

1 answer:

marusya05 [52]3 years ago

4 0

Triangle RMN and Triangle RQP
Triangle JHL and TriangleLKJ

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Select all the equations that are true when “x” is (-2).

mina [271]

Answer:

The first one, the third one, and the fourth one.

Step-by-step explanation:

i just put the ones that are correct. If you want me to write out why the incorrect ones are incorrect, let me know.

-6=3x

-6= 3(-2)

-6= -6

3. -8= x+x+x+x

-8= -2+-2+-2+-2

-8= -8

4. x/2= (-1)

-2/2 =(-1)

-1= -1

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3 years ago

Enter the unknown number for the following<br> 483 divided by __ = 21

Mice21 [21]

483 divided by 23 = 21

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3 years ago

Read 2 more answers

HELPPP what is 2x - 5 by the Square root of 9

ioda

2x-15 is the answer for 2x-5 sq 9

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3 years ago

Which of the following is a convention of graph making? question 4 options:

ki77a [65]

D=answer i think If im wrong im really sorry!

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3 years ago

Consider the diagram below. which of the following represents the values x,y and z?

Gemiola [76]

Answer:

$x=4\sqrt{6}\ units$

$y=4\sqrt{2}\ units$

$z=4\sqrt{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

In the right triangle ABD

Applying the Pythagorean Theorem

$x^2=y^2+(12-4)^2$

$x^2=y^2+64$

$y^2=x^2-64$ ----> equation A

step 2

In the right triangle BDC

Applying the Pythagorean Theorem

$z^2=y^2+4^2$

$z^2=y^2+16$

$y^2=z^2-16$ ----> equation B

step 3

In the right triangle ABC

Applying the Pythagorean Theorem

$12^2=x^2+z^2$

$144=x^2+z^2$ ----> equation C

step 4

Equate equation A and equation B

$x^2-64=z^2-16$

$x^2=z^2+48$ -----> equation D

step 5

substitute equation D in equation C

$144=z^2+48+z^2$

solve for z

$2z^2=144-48$

$2z^2=96$

$z^2=48$

$z=\sqrt{48}\ units$

simplify

$z=4\sqrt{3}\ units$

Find the value of x

$x^2=z^2+48$

$x^2=48+48=96$

$x=\sqrt{96}\ units$

$x=4\sqrt{6}\ units$

Find the value of y

$y^2=z^2-16$

$y^2=48-16$

$y^2=32$

$y=\sqrt{32}\ units$

$y=4\sqrt{2}\ units$

3 0

3 years ago