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VLD [36.1K]
3 years ago
14

Evaluate each log without a calculator

Mathematics
1 answer:
Mrac [35]3 years ago
6 0

QUESTION 1

The given logarithmic expression is

\log_4(\frac{1}{16})

We rewrite \frac{1}{16} in the index form to base 4.

This implies that;

\log_4(\frac{1}{16})=\log_4(4^{-2})

We now apply the power rule: \log_a(m^n)=n\log_a(m^n).

\log_4(\frac{1}{16})=-2\log_4(4)

Recall that logarithm of the base is 1.

\log_4(\frac{1}{16})=-2(1)

\log_4(\frac{1}{16})=-2

QUESTION 2

The given logarithm is;

\log_2(\sqrt[5]{32})

\log_2(\sqrt[5]{2^5})

This is the same as;

\log_2(2^{5\times \frac{1}{5}})

\log_2(2^{1})

\log_2(2)=1

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