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Bezzdna [24]
3 years ago
11

how to write a function "void funct()" which will accept a string from the user as input and will then display the string backwa

rd.
Computers and Technology
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

#include <bits/stdc++.h>

using namespace std;

void funct(){

   string name;

   cout<<"enter the string: ";

   cin>>name;

   

    reverse(name.begin(), name.end());

    cout<<"The string is : "<<name<<endl;

   

}

int main()

{

   funct();

 

  return 0;

}

Explanation:

create the function funct() with return type void and declare the variable type string and print a message for asking to used enter the string.  

The string enter by user is store in the variable using cin instruction.

after that, we use a inbuilt function reverse() which takes two argument.

firs argument tell the starting point and second index tell the ending point. then, the reverse function reverse the string.

name.begin() it is a function which return the pointer of first character of string.

name.end()  it is a function which return the pointer of last character of the string.

finally, print the reverse string.

for calling the function, we have to create the main function and then call the function.

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Answer:

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e.g.

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2. String variable:

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Explanation:

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3 years ago
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fiasKO [112]

Answer:

Step by step explanation along with code and output is provided below

Explanation:

#include<iostream>

using namespace std;

// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three  

void print_seconds(int hours, int mints, int seconds)

{

   int total_seconds= hours*3600 + mints*60 + seconds;

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}

// test code

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int main()

{

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   cin>>h;

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}

Output:

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enter mints if any or enter 0

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enter seconds if any or enter 0

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