For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.
for # 3:
we know A = pi r^2
We have
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04
for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92
for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582
Answer:
2x + 1=13
Step-by-step explanation:
the product of a number and 2 (2x)
sum of 1 (+1)
is 13 (=13)
Answer:
There were 7 small boxes and 14 large boxes shipped.
Step-by-step explanation:
This problem may be solved by a system of equations:
I am going to say that:
x is the number of small boxes used
y is the number of large boxes used
There were twice as many large boxes shipped as small boxes shipped
This means that y = 2x
Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.
This means that 45x + 80y =1435
So we have to solve the following system:
y=2x
45x + 80y =1435
45x + 80 (2x) = 1435
205x = 1435
x= 1435/205
x=7
y=2x= 2(7) = 14
There were 7 small boxes and 14 large boxes shipped.
M= 276 31+276=307.
307-31=276 that’s how I found M
Answer:
Step-by-step explanation:
In order to find the value of ∠EFB here, we have to note our angle relationships.
We know that ∠CFE is already 90°. We also know that ∠CFA is 90°. Angle ∠AFB is inside ∠CFA. Since we know the measure of ∠AFB, we can find the measure of ∠BFC.
Now that we know ∠CFE and ∠BFC, which together make ∠BFE, we can add these angles up.
Hope this helped!
