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Leno4ka [110]
3 years ago
10

A null hypothesis is being tested. How does the confidence level affect the testing process?

Mathematics
1 answer:
never [62]3 years ago
4 0
The confidence level C and the significance level alpha are linked through the equation

alpha = 1-C

So for instance, if the confidence level is C = 95% = 0.95 then alpha is 

alpha = 1-C
alpha = 1-0.95
alpha = 0.05

meaning we have a 5% significance level. The larger C gets, the smaller alpha gets and vice versa. It turns out that 0 < C < 1 and also 0 < alpha < 1. 

The closer C gets to 1, the alpha value gets closer to 0. The smaller alpha gets, the harder it is to reject the null. Why is that? If we have a fixed p value, say p = 0.02 then we reject the null if alpha > pvalue. But we fail to reject the null when alpha < pvalue. For very small alpha values, we're going to fail to reject H0 no matter how small the pvalue is. The pvalue would have to be really small for H0 to be rejected.

In short, I'm saying that if the confidence level is high, then the chance of rejecting the null hypothesis is low (or rare)

This is why the answer is choice A
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Lillian and Jacob work at a dry cleaners ironing shirts. Lillian can iron 25 shirts per hour, and Jacob can iron 20 shirts per h
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Answer:

Lillian worked 7h and Jacob worked 6h

Step-by-step explanation:

the number of hours Lillian worked are x (h)

the number of  hours Jacob worked are y (h)

                 (0 < x,y < 13)

=> Lilian ironed: 25x (shirts)

    Jacob ỉroned: 20y (shirts)

because Lillian and Jacob worked a combined 13 hours and ironed 295 shirts, we have:

\left \{ {{x+y=13} \atop {25x+20y=295}} \right. => \left \{ {{x=7} \atop {y=6}} \right.

so Lillian worked 7h and Jacob worked 6h

8 0
3 years ago
The first week at Javier's new job he spent $12.48, $9.50, $10.25, $4.99, and $8.59 on lunch. In the second week, he spent $3 mo
Jlenok [28]

Answer:

$0.60

Step-by-step explanation:

The mean is the average. We add up all the numbers and divide by the number of numbers.

The total for 1st week is  $12.48+$9.50+$10.25+$4.99+$8.59 = $45.81

Now, the mean:

Mean = 45.81/5 = $9.162

2nd week's total is 3 more than last week's total, so 2nd week's total is:

45.81 + 3 = $48.81

Now, Mean:

Mean = 48.81/5 = $9.762

The increase is  9.762 - 9.162 = $0.60

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Answer:

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