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3 years ago

A principal of $4400 is invested at 8.25% interest, compounded annually. how much will the investment be worth after 15 year's?

1 answer:

vladimir2022 [97]3 years ago

3 0

A = $ 9,845.00

Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 8.25%/100 = 0.0825 per year,
then, solving our equation

A = 4400(1 + (0.0825 × 15)) = 9845
A = $ 9,845.00

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 4,400.00
at a rate of 8.25% per year
for 15 years is $ 9,845.00.

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kotykmax [81]

Answer:

336

Step-by-step explanation:

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3 years ago

A video game designer is modeling a tower that is 320 ft high and 260ft wide. She creates a model so that the similarity ratio o

maksim [4K]

H = Tower Height = 320
W = Tower Width = 260
h = Model Height
w = Model Width

h = (1/500) * H = (1/500) * 320 = .64 feet
w = (1/500) * W = (1/500) * 260 = .52 feet

Now, we need to convert these measurements to inches.

There are 12 inches per foot.

Let x = height in inches and y = width in inches

The ratio below compares feet to inches

x / h = 12 in / 1 ft
y / w = 12 in / 1 ft

Plug in h and w, cross multiply, and solve for x and y, respectively.

x / .64 = 12 / 1
1 * x = .64 * 12
x = 7.68 in

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5 0

3 years ago

Hello what is the answer to this and the domain

nlexa [21]

We are given the following functions:

$\begin{gathered} f(x)=7\sqrt[]{x}+6 \\ g(x)=x+6 \end{gathered}$

We are asked to determine the composite function:

$(f\circ g)(x)$

The composition of functions is equivalent to:

$(f\circ g)(x)=f(g(x))$

Therefore, we replace the value of "x" in function "f" for the function "g", therefore, we get:

$(f\circ g)(x)=f(g(x))=7\sqrt[]{x+6}+6$

Since we can't simplify any further this is the composition.

Now we are asked to determine the domain of this function. Since we have a square root, the domain must be the values of "x" where the term inside the radical is greater or equal to zero, therefore, we have:

$x+6\ge0$

Now we solve for "x" by subtracting 6 from both sides:

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3 0

1 year ago

Suppose the mean height of women age 20 years or older in a certain country is 62.7 inches. One hundred randomly selected women

zmey [24]

Answer: No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

Step-by-step explanation:

Since we have given that

$H_0:\mu =62.7\\\\H_a:\mu \neq 62.7$

Mean height = 61.5 inches

Standard deviation = 4.4 inches

n = 100

So, test statistic value would be

$z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{61.5-62.7}{\dfrac{4.4}{\sqrt{100}}}\\\\z=\dfrac{-1.2}{0.44}\\\\z=-2.727$

At 10% level of significance, in two tail test ,

z = 1.28

Since 1.28 > -2.727

So, we will accept the null hypothesis.

Hence, No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

7 0

4 years ago

Please help me with this question

saul85 [17]

Given:
ML = 2.3
Angle L = 70 degrees

What we want to find:
MN = x

Use the sine rule
Make sure your calculator is in degree mode

sin(angle) = opposite/hypotenuse
sin(70) = x/2.3
2.3*sin(70) = x
x = 2.3*sin(70)
x = 2.16129302780759
x = 2.2

-------------------------------
Answer: 2.2

7 0

3 years ago