recalling that d = rt, distance = rate * time.
we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?
so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.
then Wanda kicks in, rolling like a lightning at 16mph.
let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.
the distance both have travelled is the same "d" miles, reason why they "meet", same distance.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20Hector%26d%2612%26t%2B%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B1em%5D%20Wanda%26d%2616%26t%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D%2812%29%5Cleft%28%20t%2B%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5C%5C%5B1em%5D%20d%3D%2816%29%28t%29%20%5Cend%7Bcases%7D)
For all positions: 24% for part time that needs experience
8% full time needs experience
32% part time need experience
36% full time no experience needed
kinda need a little bit more details for statistics.
"Note how for each (x,y) pair of points given we see that x*y = 60
For instance, the point (4,15) has x = 4 and y = 15 so x*y = 4*15 = 60
Another example: (x,y) = (6,10) means x = 6 and y = 10, so x*y = 6*10 = 60
The fact that this is true for ALL of the points shown indicates we have an inverse variation of the form x*y = k where k = 60 in this case.
Therefore, the answer is B.) An inverse function is the best model because the products of corresponding x- and y-values are equal."
Answer:
$45
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
For a walk-a-thon a sponsor committed to give you a flat fee of $5 plus $2 for every mile you walk. If you walk for 20 miles, what is the total amount you will collect from your sponsor at the end of the walk-a-thon?
$5 was given for participants of the walk-a-thon.
$2 was given for every miles won
Then, for "y" number of miles, the the amount that can be won is ( 2×y)= 2y
The Total amount that can be given
= (5 + 2y)
Where "y" is the miles value
Then, if you walk for 20 miles, The Total amount that can be given
= 5 + 2(20)
= 5+ 40
= $45
