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Radda [10]
3 years ago
13

Help with #15, please show all work, will mark brainliest!

Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0

Measure of ∠B is 110°

Step-by-step explanation:

  • Step 1: Find ∠B of the parallelogram.

In a parallelogram, opposite angles are equal.

⇒ ∠B = ∠D

⇒ ∠B = (5x + 10)°

  • Step 2: Use theorems of quadrilaterals to form equations to find x and y.

Now, angles in a parallelogram are equal to 360°.

⇒ ∠A + ∠B + ∠C + ∠D = 360°

⇒ (3x + y)° + (5x + 10)° + (5y + 20)° + (5x + 10)° = 360°

⇒ 13x + 6y + 40° = 360°

⇒ 13x + 6y = 320°  ------ (1)

Also, adjacent angles in a parallelogram are supplementary.

⇒ ∠A + ∠D = 180°

⇒ (3x + y)° + (5x + 10)° = 180°

⇒ 8x + y = 170° ----------- (2)

  • Step 3: Solve the 2 equations to find x and y.

13x + 6y = 320

48x + 6y = 1020  (After multiplying eq. 2 with 6 to make coefficients equal)

Subtract (2) from (1)

⇒ -35x = -700

∴ x = 20

⇒ (5x + 10)° = 100 + 10 = 110°

storchak [24]3 years ago
6 0

Answer:

110°

Step-by-step explanation:

Angle A = Angle C

3x + y = 5y + 20

3x = 4y + 20

Angle C + Angle D = 180

5y + 20 + 5x + 10 = 180

5x + 5y = 150

x + y = 30

x = 30 - y

3(30 - y) = 4y + 20

90 - 3y = 4y + 20

7y = 70

y = 10

x = 30 - 10

x = 20

Angle B = Angle D

= 5(20) + 10

= 110°

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denpristay [2]

Answer:

(i) Five number summary: Minimum value = 1, Q_1=18,Median=18.5, Q_3=20.5, Maximum value = 26.

(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.

(iii) 26 is an outlier of the data.

Step-by-step explanation:

The given data set is

19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21

Arrange the data set in ascending order.

16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26

Divide the data set in 4 equal parts.

(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)

Minimum value = 16

Q_1=\frac{18+18}{2}=18

Median=Q_2=\frac{18+19}{2}=18.5

Q_3=\frac{20+21}{2}=20.5

Maximum value = 26

The inter quartile range (IQR) of the data is

IQR=Q_3-Q_1=20.5-18=2.5

Upper fence :

Q_3+1.5(IQR)=20.5+1.5(2.5)=24.25

Lower fence :

Q_1-1.5(IQR)=18-1.5(2.5)=14.25

If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.

26 ∉ [14.25, 24.25]

Therefore, 26 is an outlier of the data.

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The random sample of the students is an illustration of sampling

The chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

<h3>How to determine the reason chi square is not appropriate?</h3>

The dataset is given as:

Monday        34

Tuesday       29

Wednesday   32

Thursday        28

Friday             19

The variable of the above dataset is a not a categorical dataset.

One of the conditions of the chi-square test for goodness of fit test is that the variable under study must be categorical.

Hence, the chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.

Read more about chi-square test at:

brainly.com/question/19959558

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Answer:

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Step-by-step explanation:

the answer is the negative reciprocal.

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