Given P(A) 0.169, P(B) 0.041, and P(C) 0.172, and that events A, B, and C are mutually exclusive, what is the P(A or B or C)? An

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4 years ago

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swer in decimal form. Round to 3 decimal places as needed Your Answer: Answer

1 answer:

o-na [289] · Answer 1 · 2021-12-17T09:16:48+03:00

Answer:

The value of P(A or B or C) is 0.382.

Step-by-step explanation:

Given,

P(A) = 0.169,

P(B) = 0.041,

P(C) = 0.172

Since, if events A, B and C are mutually events ( in which no element is common ),

Then, P(A∪B∪C) = P(A) + P(B) + P(C)

Or P(A or B or C) = P(A) + P(B) + P(C),

By substituting the values,

P(A or B or C) = 0.169 + 0.041 + 0.172 = 0.382