<h3>
Answer:</h3>
1/17 or 0.0588 (without replacement)
<h3>
Step-by-step explanation:</h3>
To answer this question we need to know the following about a deck of cards
- A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
- Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
- Additionally, there are 13 cards in each suit (Clubs/Spades are black, Hearts/Diamonds are red)
.
In this case, we are required to determine the probability of choosing two diamonds.
- There are 13 diamonds in the deck.
- Assuming, the cards were chosen without replacement;
P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)
P(First card is diamond) = 13/52
If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.
Therefore;
P(Second card is diamond) = 12/51
Thus;
P(Both cards are diamonds) = 13/52 × 12/51
= 156/2652
= 1/17 or 0.0588
Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.
Answer:
Condition 1:
four times the sum of X and Y = 4(X + Y)
Condition 2:
the sum of four times X and Y= 4X + Y
In condition 1, both the variables are first added and then multiplied by four. This can be simplified as:
4X +4Y
I condition 2, only the variable X is multiplied with 4 and then added to Y.
With positive integers, condition 1 will always give a greater value.
With negative integers, condition 2 will have greater value.
I hope it will help you!
Answer:
daylilies - $12; ivy - $7
Step-by-step explanation:
one way to answer this question is by using two equations
first write your let statements
let d be daylilies and let i be ivy
7d + i = 91
7d + 3i = 105
then you can subtract the equations
you get -2i = -14
then divide eveything by -2
i = 7
ivy costs $7
lastly plug this into an equation
7d + 7 = 91
7d = 84
d = 12
daylilies cost $12