PART A:
NET A IS THE CORRECT ANS... NET B IS WRONG
PART B:
AB is... 3 in.
BC is... 4 in.
CD is... 7.2 in.
PART C:
A=ah+bh+ch+1
2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=7.2·5+4·5+4·5+1
2·﹣7.24+2·(7.2·4)2+2·(7.2·4)2﹣44+2·(4·4)2﹣44 ≈88.55363
So, the surface area is 88.55
<em>Hope it helps...</em>
