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3 years ago

State if the two triangles are congruent. If they are, state how you know.

Mathematics

2 answers:

ki77a [65]3 years ago

5 0

The first picture

The two triangles are proved by SSS (SIDE-SIDE-SIDE)

Reason: As you can see, there are marks on the sides of the triangle (three line marks and two line marks). Those marks represent congruence.

The second picture

The two triangles are congruent from Angle-Angle-Side. Try to picture the first triangle by rotating it the same way as the second triangle. You can see the marks and angles are the same.

dangina [55]3 years ago

3 0

Answer:

first triangle is congruent because of SSS Postulate in which two sides are same and one side is common

second triangle is congruent because of SAS postulate

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How many pounds of cashews that cost $14 per pound must be mixed with 5 pounds of peanuts that cost $6.50 per pound to make mixe

Fantom [35]

The amount of cashew mixed is 5 pounds

<h3>Word problem on total cost</h3>

Cost of 1 pound of cashew = $14

Cost of 1 pound of peanut = $6.50

Total cost of 1 pound of the mixed nuts = $10.25

Cost of 5 pounds of peanuts = 5 x $6.50

Cost of 5 pounds of peanuts = $32.50

Let the amount of cashew be x

Total cost of x cashew = 14x

Total amount of the mixed nuts = x + 5

Total cost of the mixed nuts = 10.25(x+5)

Total cost of the mixed nuts = 10.25x + 51.25

14x + 32.50 = 10.25x + 51.25

14x - 10.25x = 51.25 - 32.50

3.75x = 18.75

x = 18.75/3.75

x = 5

Therefore, the amount of cashew mixed is 5 pounds

Learn more on word problem on cost here: brainly.com/question/21405634

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8 0

2 years ago

Read 2 more answers

Which of the following shows as a mixed number and as an improper fraction?

Marysya12 [62]

There's no following. You need to post a picture or complete the question.

6 0

4 years ago

Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera

Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = $\frac{1}{2}(\text{Base})\times (\text{Height})$

Area of ΔADC = $\frac{1}{2}(\text{CD})(\text{AD})$

= $\frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})$

= $\frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)$

= $\frac{1}{2}(\sqrt{169-144})(12)$

= $\frac{1}{2}(5)(12)$

= 30 cm²

Area of equilateral triangle II = $\frac{\sqrt{3} }{4}(\text{Side})^2$

Area of equilateral triangle II = $\frac{\sqrt{3}}{4}(13)^2$

= $\frac{(1.73)(169)}{4}$

= 73.0925

≈ 73.09 cm²

Area of rectangle III = Length × width

= CF × CD

= 7 × 5

= 35 cm²

Area of trapezium EFGH = $\frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})$

Since, GH = GJ + JK + KH

17 = $\sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}$

12 = $\sqrt{81-x^2}+\sqrt{225-x^2}$

144 = (81 - x²) + (225 - x²) + 2 $\sqrt{(81-x^2)(225-x^2)}$

144 - 306 = -2x² + $2\sqrt{(81-x^2)(225-x^2)}$

-81 = -x² + $\sqrt{(81-x^2)(225-x^2)}$

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = $\frac{1}{2}(5+17)(9)$

= 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

= 237.09 cm²

7 0

4 years ago

Two othice desks that are

alex41 [277]

Answer:

Research shows that many students who leave school without finishing year 12 will: earn less money when they start work. be more likely to have long periods of unemployment. be less likely to return to study later in life.١٢‏/١٠‏/٢٠١٨

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which of the following equations have no solutions?

azamat

Answer:

A, B & D

Step-by-step explanation:

Because if you subtract one of the constants from both sides then you should only have equal variables. In other words, both sides have to be identical in this situation.

33x-33= 33x + 25

33x = 33x + 58 No matter what you make x, the right will be 58 bigger than the right so there is no solution.

33x+33=33x+25

33x+8= 33x nope no solution

33x+25=33x+25

33x = 33x both sides identical so there is a solution

33x-25 = 33x +25

33x= 33x+50

4 0

3 years ago