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Agata [3.3K]
2 years ago
10

1. In 2011, Molly and Jerry both went to

Mathematics
1 answer:
True [87]2 years ago
6 0

Answer:

2017

Step-by-step explanation:

Molly goes every 2 years

Jerry goes every 3 years

LCM(2,3) = 2 x 3 = 6

2011 + 6 = 2017

The answer is 2017

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C

Step-by-step explanation:

0.38 = 19/50

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How do you get angle x using trigonometry in a right angled triangle?
Scorpion4ik [409]

Answer:

Example

Step 1 The two sides we know are Adjacent (6,750) and Hypotenuse (8,100).

Step 2 SOHCAHTOA tells us we must use Cosine.

Step 3 Calculate Adjacent / Hypotenuse = 6,750/8,100 = 0.8333.

Step 4 Find the angle from your calculator using cos-1 of 0.8333:

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2 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Hey im in online class RN can does anyone know what (-4) – 2 = please respond early
rjkz [21]

Answer:

(-4) – 2 = -6

Hope This Helps.!! :)

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2 years ago
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