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3 years ago

Plz help..................refresh page before u answer

Mathematics

1 answer:

S_A_V [24]3 years ago

8 0

$\dfrac{7}{x^2-36}-\dfrac{1}{x-6}=\dfrac{7}{(x+6)(x-6)}-\dfrac{1}{x-6}=\\\\\\=
\dfrac{7}{(x+6)(x-6)}-\dfrac{(x+6)}{(x+6)(x-6)}=\dfrac{7-x-6}{(x+6)(x-6)}=\boxed{\dfrac{1-x}{(x+6)(x-6)}}$

Answer B.

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3 years ago

Three right triangles are drawn in the coordinate plane,

SashulF [63]

Answer:

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Step-by-step explanation:

Let's find the distance of the legs for the 3 right triangles.

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The smaller leg (SL) is from (2,5) to (2,8), so the length is given by the distance in the y-axis:

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Hence, the lenght of the smaller leg is 3.

The longer leg (LL) is from (-8, 8) to (2, 8), so the length is given by the distance in the x-axis:

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Then, the length of the longer leg is 10.

Now, we can find the hypotenuse (H) by using Pitagoras:

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Triangle B

The SL is from (3, -9) to (7, -9)

The length of the SL is:

$SL_{B} = 7 - 3 = 4$

The LL is from (7, -9) to (7, 4)

The length of the LL is:

$LL_{B} = 4 - (-9) = 13$

The hypotenuse is:

$H_{B} = \sqrt{4^{2} + 13^{2}} = 13.6$

Triangle C

The SL is from (-10, -6) to (-10, -1)

The length of the SL is:

$SL_{C} = -1 - (-6) = 5$

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The length of the LL is:

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The hypotenuse is:

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I hope it helps you!

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