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lubasha [3.4K]
3 years ago
9

PLEASE HELP ME FIGURE OUT WHAT TO PUT IN THE QUESTION MARKS

Mathematics
1 answer:
lutik1710 [3]3 years ago
5 0
6 x 4 = 24 
6 x 94 = 564
So now we just have to find what the 1 question mark is because we already know that the last question mark is 564. Now we just have to find the one right next to the 6.
6 x 90 = 540
540 + 24 = 564
We got our answer! 
the equation should look like this.
6 x 94 = 6 x 90 + 6 x 4 = 564.
I hope this helped you out!
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HELP PLEASE!! BRAINLIEST AND 10 POINTS!! if the sixth term of a geometric sequence is 224, and the eleventh term is 7168, what i
Klio2033 [76]
The first term should be 7

a1 = (224) / (2)6 - 1 = 7
8 0
3 years ago
Lauren,Amanda,and Cami each buy the same pizza.Cami eats 1/2 of her pizza.Amanda eats less than Cami.Lauren eats more than Cami.
Harrizon [31]
Amanda could’ve ate 1/4 and Lauren could’ve ate 3/4. I hope this helps!
6 0
4 years ago
7=m/5 what is the answer
Artyom0805 [142]
7 = m/5
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6 0
4 years ago
Eric’s average income for the first 4 months of the year is $1,450.25, what must be his
drek231 [11]

Answer:

Average income of Eric for the remaining 8 months = \$1946

Step-by-step explanation:

Given: Average income of Eric for the first 4 months of the year is equal to  $1,450.25

To find: average income for the remaining 8 months so that his average income for the year is  $1,780.75

Solution:

Average income = Total income for the year/Total number of months

Average income of Eric for the first 4 months = $1,450.25

So,

Total income of Eric for the first 4 months = 1,450.25 × 4 = 5801

Let x denotes total income of Eric for the remaining 8 months

Total income for the year = 5801 + x

Therefore,

Average income for the year = \frac{5801+x}{12}

Also, average income for the year is  $1,780.75

1780.75=\frac{5801+x}{12}\\1780.75\times 12=5801+x\\21369=5801+x\\21369-5801=x\\15568=x

Total income of Eric for the remaining 8 months = $15568

Average income of Eric for the remaining 8 months = \frac{15568}{8}=\$1946

7 0
3 years ago
5+m>4 or 7m<-35 please help!
puteri [66]
5+m>4 \ \hbox{or} \ 7m4 \\
m>4-5 \\
m>-1 \\ \\
7m
3 0
4 years ago
Read 2 more answers
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