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yulyashka [42]
3 years ago
11

Stages

Mathematics
1 answer:
solong [7]3 years ago
6 0
Don't get the question wish i could help :(( sorry
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Which of the following scenarios will most negatively impact a credit score?
slamgirl [31]
Excessive returning of items
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3 years ago
Estimate a 15% tip on a lunch bill of $78.42 by first rounding the bill amount to the nearest ten dollars.
Ludmilka [50]

Answer:

The tip is $12

Step-by-step explanation:

78 rounds up to 80.

15x80=1200.

1200/100=12.

4 0
3 years ago
Find two positive numbers such that the ratio of the two numbers is 7 to 3 and the product of the two numbers is 525.
lbvjy [14]

Answer:

35 and 15

Step-by-step explanation:

Process of elimination:

Try 105 and 5 - 105 is way too much and 5 is way too little. We know that they are between 5 and 105.

Try 50 and 10.5 - This is closer, but 50 is still too much and 10.5 is too little. We now know that the two numbers are between 10.5 and 50

Try 30 and 17.5 - This is very close, but now 30 is not enough and 17.5 is too much. We now know that the smaller number is between 10.5 and 17.5 as well as the larger number is between 30 and 50.

Try 40 and 13.125 - This is also very close, but 40 is too much and 13.125 is too little. We now know that the lower number is between 13.125 and 17.5 as well as the larger number is between 30 and 40.

Try 35 and 15 - Success: 35 and 5 make the simplified ratio of 7:3! They also are products of 525!

7 0
3 years ago
What is the vertical asymptote for f(x)=2 over x-3
Simora [160]
The vertical asymptote will occur when the denominator is equal to zero, which makes f(x) approach ±oo and occurs about the vertical line x=3
4 0
3 years ago
Choose the best description of the roots of the equation 3x 2 - 4x + 5 = 0.
Naily [24]
For this case we have the following polynomial:
 3x ^ 2 - 4x + 5 = 0

 Using the resolver we have:
 x =  \frac{-b +/-  \sqrt{b^2 - 4ac}}{2a}
 Substituting values we have:
 x =  \frac{-(-4) +/-  \sqrt{(-4)^2 - 4*3*5}}{2*3} 


 x =  \frac{4 +/-  \sqrt{16 - 60}}{6}
 x =  \frac{4 +/-  \sqrt{-44}}{6}
 x =  \frac{4 +/-  \sqrt{-4*11}}{6}
 x =  \frac{4 +/-  2\sqrt{-11}}{6}
 x =  \frac{2 +/-  \sqrt{-11}}{3}
 x = \frac{2 +/- i\sqrt{11}}{3}
 Answer:
 
We observe that the solution to the quadratic equation are two imaginary roots.
7 0
3 years ago
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