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vovikov84 [41]
3 years ago
10

How do u do those two questions

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0
God loves you and will guide you to the anwser will external interference
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How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=
\begin{cases}
-7\\
1
\end{cases}
\\\\\\
\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}
\\\\\\
x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
Graph the line below x-3y=3 yellow dark green dark blue red
Feliz [49]
What do you mean by this?
7 0
4 years ago
What is the image of the point (-9, -8) after a rotation of 90° counterclockwise
LUCKY_DIMON [66]

Answer:

-x,y

Step-by-step explanation:

7 0
4 years ago
What is the Mean for the given data: 2, 8, 7, 6, 6, 3, 4.4, 5.1, 9, 8
kotegsom [21]

Answer

5.9

Step-by-step explanation:

The mean of a set of numbers is the sum divided by the number of terms

7 0
3 years ago
Some people say that more babies are born in september than in any other month. to test this claim, you take a simple random sam
4vir4ik [10]
Answer: Yes, 21 is higher than what you would expect if September was like any other month.

There are 12 months in the years. If all months were equally likely, then they would each have 1/12 of the babies.

1/12 of 150 is 12.5. The expected number of babies per month would be 12.5.

However, in the sample, there were 21 babies in September.
4 0
3 years ago
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