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Ilia_Sergeevich [38]
3 years ago
15

L'Hospital's Rule Lim X approaches 0 cot2x•sin6x

Mathematics
1 answer:
77julia77 [94]3 years ago
3 0
\bf \lim\limits_{x\to 0}\ cot(2x)sin(6x)\implies \lim\limits_{x\to 0}\ \cfrac{cos(2x)}{sin(2x)}sin(6x)\\\\
-----------------------------\\\\
\underline{LH}\qquad \cfrac{-2sin(2x)sin(6x)+cos(2x)6cos(6x)}{2cos(2x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{-2sin(2x)sin(6x)+cos(2x)6cos(6x)}{2cos(2x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{-0\cdot 0+1\cdot 6\cdot 1}{2\cdot 1}\implies \cfrac{6}{2}\implies 3
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I don't know how to solve this, sr

Hope this helped :3

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