Question

Permutation, solve for n: nP3 = 17(nP2)

Answer 1

$nP3=\frac{n!}{(n-3)!}$
$17(nP2)=17(\frac{n!}{(n-2)!})$
Therefore we can write the equation as follows:
$\frac{n!}{(n-3)!}=17(\frac{n!}{(n-2)!})$
Dividing both sides by n!, we get:
$\frac{1}{(n-3)!}=\frac{17}{(n-2)!}$
$\frac{(n-2)!}{(n-3)!}=17$
Therefore n - 2 = 17 and n = 19
The answer is: n = 19