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Sunny_sXe [5.5K]
3 years ago
8

What is the standard form of equation of a circle with center at (-2, -3) and passing through the point (-2, 0)?

Mathematics
1 answer:
Rashid [163]3 years ago
3 0
Hello :
an equation of the circle <span>Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2  and b =-3  (</span><span>Center A(-2,-3))
r = AP......(P(-2,0))
r² = (AP)²
r² = (-2+2)² +(-3-0)² = 9
</span><span>an equation of the circle that satisfies the stated conditions.
Center </span> A(-2,-3) , passing through P(-2, 0) is : (x+2)² +(y+3)² = 9
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3x+9y=12 <br>-3x-6y=18 <br>Solve the system by using elimination​
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Answer:  (x, y) = (-26, 10)

This means x = -26 and y = 10 pair up together

===============================================================

How to get that answer:

Add the equations straight down. Think of having 3 separate columns for the three different like terms.

  • 3x + (-3x) becomes 0x and that's just 0. So the x terms go away
  • 9y + (-6y) is the same as 9y-6y which turns into 3y
  • 12 + 18 becomes 30

After all that, we're left with the simpler equation 3y = 30. That solves to y = 10 after dividing both sides by 3.

Plug this back into any equation involving x and y. Solve for x

3x+9y = 12

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3x+90 = 12

3x = 12-90

3x = -78

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x = -26

We have found that x = -26 and y = 10 pair up together to form the solution.

-------------------

Checking the answer:

Plug (x,y) = (-26, 10) into the first equation

3x+9y = 12

3(-26)+9(10) = 12

-78+90 = 12

12 = 12

We get a true equation since the same thing is on both sides.

Repeat the same idea for the second equation

-3x-6y = 18

-3(-26) - 6(10) = 18

78 - 60 = 18

18 = 18

The second equation is true as well.

Both equations are true, so the solution (x, y) = (-26, 10) is confirmed.

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