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4 years ago

3

Solve: StartFraction 2 Over 3 EndFraction minus 4 x plus StartFraction 7 Over 2 EndFraction equals negative 9 x plus StartFracti

on 5 Over 6. EndFraction. – 4x + = –9x +

2 answers:

iren [92.7K]4 years ago

7 0

Answer: $x=-\frac{2}{3}$

Step-by-step explanation:

Given the following equation:

$\frac{2}{3}-4x+\frac{7}{2}=-9x+\frac{5}{6}$

We need to solve for "x":

1. Move the fractions to one side of the equation and the x-terms to the other side:

$-4x+9x=\frac{5}{6}-\frac{2}{3}-\frac{7}{2}$

2. Add the like terms.

To add the fractions we must find the Least Common Denominator (LCD):

$6=2*3\\3=3\\2=2\\\\LCD=2*3=6$

Then:

$5x=\frac{5-4-21}{6}\\\\5x=-\frac{20}{6}\\\\5x=-\frac{10}{3}$

3. Finally, divide both sides of the equation by 5:

$\frac{5x}{5}=\frac{-\frac{10}{3}}{5}\\\\x=-\frac{2}{3}$

RoseWind [281]4 years ago

3 0

Answer:

the correct answer is -2 1/8

Step-by-step explanation:

i did the question on edge 2020 :>

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Which expression converts 8 radians to degrees?

deff fn [24]

52 have a blessed day ‍hdhd dndjfjfjjg

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3 years ago

How will the volume of the pyramid change if each side is multiplied by a factor of 5?

o-na [289]

The volume of the pyramid is changed by a factor of 125

<u>Solution:</u>

Given that, each side of a pyramid is multiplied by a factor of 5.

We have to find how will the volume of the pyramid changes?

Now, we know that, volume of a pyramid $=\frac{\text {length} \times \text { breadth } \times \text {height}}{3}$

Now, each dimension is multiplied by factor of 5.

Then, volume of new pyramid $=\frac{(5 \times l e n g t h) \times(5 \times \text { breadth) } \times(5 \times \text { height })}{3}$

$=5 \times 5 \times 5 \times \frac{\text { length } \times \text {breadth\timesheight}}{3}$

Volume of new pyramid = 125 $\times$ volume of old pyramid.

Hence, the volume of the pyramid is changed by a factor of 125.

7 0

3 years ago

Can someone please help me this question and explain/show your work to get that answer??

pishuonlain [190]

If the number increases each year, then the 15% starts with a bigger number each year.

The first increase raises 300 million to (1.15 times 300 million) = 345 million.

The next increase raises 345 million to (1.15 times 345 million) = 396.75 million.

and so on and so on.

This is just like compound interest in a bank.  Each time the bank
pays you interest on your savings, it pays interest on a bigger amount.

In this problem, the number of cars increases

... at the end of 2000 / beginning of 2001
   ... at the end of 2001 / beginning of 2002
   ... at the end of 2002 / beginning of 2003
   ... at the end of 2003 / beginning of 2004 .

That's four times. Each increase raises it 15% higher than it was before.
So you need to find

(1.15) · (1.15) · (1.15) · (1.15) of 300 million.

The way to write that is

(300 million) · (1.15)⁴ =     524 million 701 thousand 875 cars.

Rounded to the nearest whole million, that's 525 million.

8 0

4 years ago

, write two equivalent fractions for each given fraction.<br> 4/10=

san4es73 [151]

4/10 is equal to 8/10 and 12/30

6 0

3 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

4 years ago