Answer by JKismyhusbandbae: So this is really simple. You are probably making this out harder than it needs to be. Consider the set of ordered pairs {(-1,0), (4,-5), (6,-6), (9,11), (10,14)}. This set of ordered pairs is a function because for each value of x there is one and only one y-value. This means that the x value never repeats. Therefore any function is a function when the x value never repeats.
Looking at the table we want to find all it's ordered pairs: (0,4), (1,2), (2,3), (3,9), (4,1).
F(2) is 3 so when x equals 2.
So the ordered pair is (2,3) 2 is the x value and the f(2) is 3.
Answer:
8 weeks
Step-by-step explanation:
Since we know that the sunflower in Class B has a rate of 1/4 less, we know that it will eventually catch on to sunflower A.
First, we have to look at the difference which is 2. How many 1/4ths makes 2?
8.
Therefore, 8 weeks would be your answer.
<em>-kiniwih426</em>
Answer:
<h2>a = -2, b = -2 </h2>
Step-by-step explanation:
Step-by-step explanation:
An exponentially decaying signal is of the form x(t) = Ce^(-αt) in terms of an initial value C and a decay rate α > 0. The signal equals a fraction 1/e of its initial value after the characteristic time scale t = 1/α.
Given
x(t) = 2e^(-t/3) + e^(-t) + 3e^(-t/2)
The decay rates are: 1/3, 1, and 1/2.
The slowest decay rate α is the minimum of {1/3, 1, 1/2} = 1/3.
The corresponding time scale
is only 2/3 times larger than the next faster decay rate 1/2, so the decay rates are NOT well separated. The slowest component is larger than 0.5 as long as t < (ln3)/0.5 ≈ 2.2.
The other two components add
up to more than the value of the slowest component. We conclude that the component with slowest decay rate dominates measurements on any interval even in the presence of noise.
Answer:
x≤50
Step-by-step explanation:
100-3x≥-50
subtracting 100 at both side on inequality
-100+100-3x≥--50-100
-3x≥-150
Dividing both sides by 3
-3x/3≥-150/3
-x≥--50
Adding 50 on both sides
-x+50≥-50+50
-x+50≥0
Adding x on both sides
-x+x+50≥0+x
50≥x
so,
x≤50
