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Marysya12 [62]
3 years ago
10

Gio is studying the rectangular pyramid below.

Mathematics
2 answers:
Irina18 [472]3 years ago
7 0

Answer:

a he used the wrong values as the bases of the lateral faces.

Step-by-step explanation:

3241004551 [841]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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I have no idea what this is since I was absent and my teacher is didn’t it explain it to me, someone?
MatroZZZ [7]

Answer:

Step-by-step explanation:

4 0
3 years ago
ms adams shares out 40 pencils between niamh and jack in the ratio 3:5 how many pencils does each child get
Neporo4naja [7]
40 times 3/3+5= Niamh’s amount = 40x3/8 = 15 pencils
40 times 5/3+5= Jack’s amount =
40x5/8 = 25 pencils
5 0
3 years ago
Read 2 more answers
True or False: The relation {(3, 2), (1, 2), (7, –5), (11, 6), (17, –4), (13, 8)} is a function.
8090 [49]

Answer:

False

Step-by-step explanation:

This is because if you have a function which is Y=2x-4 , then trying to give an example using the given points which (3,2) , here we will have Y=2 upon replacing 3 in the function cause 3 is the value of x and vice versa if we have 2 as the value of Y then x will be 3 . However,if we get the (1,2) the answer for Y will be -2 which is different from the one we have in the question hence this concludes false

7 0
3 years ago
3 consecutive integers for 273
a_sh-v [17]

Answer:

90, 91 and 92

Step-by-step explanation:

Given

Consecutive integers = 273

Required

Find the integers

The question seem to be incomplete. However, I'll assume we're dealing with sum.

Let the smallest integer be y.

So,

y + y + 1 + y + 2 = 273

Collect like terms.

y + y + y = 273 - 2 - 1

3y = 270

Divide both sides by 3

y = 90

Hence, the integers are 90, 91 and 92

8 0
3 years ago
Find the indefinite integral using the substitution provided.
Nady [450]

Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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