In the figure below, triangle ABC is similar to triangle PQR, as shown below:

What are the coordinates of the terminal point determined by t=20pi/3?

attashe74 [19]

Answer:

(- 1/2 , √3/2)

Step-by-step explanation:

t=20π/3

t' = 20π/3 - 6π = 2π/3 (120°) ... 2nd quadrant

If we start from (1,0) of unit circle, the coordinate of terminal point (x,y)

OF/OE = - cos 60° = x / 1 = - 1/2

FE/OE = sin 60° = y/1 = √3/2

3 0

3 years ago

The proof that AMNS AQNS is shown.

FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ

In ΔMNS and ΔQNS

MN=QN (∵ MNQ is isosceles triangle)

∠NMS=∠NQS (∵ MNQ is isosceles triangle)

MS=SQ (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0

3 years ago

Can’t figure out M<7/12 The options are A.1 B.-1 C.-9 D.-5

sladkih [1.3K]

M < 7 / 12

(1) < 7 / 12

(1) < 0.583333333 (false statement)

(-1) < 7 / 12

(-1) < 0.583333333 (true statement)

(-9) < 7 / 12

(-9) < 0.583333333 (true statement)

(-5) < 7 / 12

(-5) < 0.583333333 (true statement)

B C D maybe?

8 0

3 years ago

A carpet layer is given a roll of carpet which has already been cut for a 12-ft. wall. The wall measures 1.5 in. on a drawing. T

Anestetic [448]

Answer:

It is 48

Step-by-step explanation:

8 0

3 years ago

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago