R = d/2 = 4/2 = 2 in
A = π r^2 = π (2)^2 = 4<span>π
answer
</span>4<span>π in^2</span>
Answer:
<h2>length= 40cm</h2><h2>width= 120cm</h2><h2>
Step-by-step explanation:</h2>
Area of a rectangle= lenght× width
Dimensions of 1st rectangle: L,W
Dimensions of 2nd rectangle: L+10; W+4
Hence,
LW = 480__________(1)
(L-10)(W+4) = 480_______(2)
LW = LW+4L - 10W - 40
4L = 10W +40
2L = 5W + 20
L = (5/2)W + 10_________(3)
But LW = 480 (from equation one)
So, W = 480/L
substitute as= 480/L into equation (3)
L = (5/2)(480/L)+10
L = 1200/L + 10
L^2 - 10L - 1200 = 0
factorising.
we're have,
(L-40)(L+30) = 0
therefore, since L can't be negative , L = 40
L = 40 cm (length)
Then 480/L = W = 120 cm (width)
<h2>therefore L= 40cm and W= 120cm</h2>
You'll have <span>$634.87 after 6 years at 4% compounded quarterly, thus B:
You'll have </span><span>$3,619.80 after 6 months at 6.75% compounded monthly, thus A:
</span>Formulas where n = 1 (compounded once per period or unit t)
1. Calculate Accrued Amount (Principal + Interest) A = P(1 + r)^t
2. Calculate Principal Amount, solve for P. P = A / (1 + r)^t
4. Calculate the rate of interest in decimal, solve for r. r = (A/P)1/(^t - 1)
5. Calculate rate of interest in percent. ...Calculate time, solve for t.
An algebraic phrase or expression is a mixture of integer constants, variables and algebraic operations like addition, subtraction, multiplication, division and exponentiation. In this problem, you need to isolate first what is grouped together or what needs to be done first which in this sentence, "the sum of negative three-eighths and four. By substitution, it would be (-3/8+4). Then you multiply their sum by x so it would result to (-3/8+4)x. After that it is said that you need to minus that to nine times z which is 9z. This will result to an expression like this (-3/8 +4)x-9z. In the simplest term, the answer would be 9/8x-9z.
