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Olin [163]
3 years ago
11

A student is driving a car at 60.0 miles/hour. what is its speed in m/s

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0
60 miles per hour.
So there are 3600 seconds in 1 hour.
60/3600

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Stan has a rectangular piece of carpet with an area of 23.4 square meters. The piece of carpet is 13 meters long. What is the wi
Sholpan [36]

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u>

The breadth of rectangular carpet is 1.8 m.

<u>S</u><u>t</u><u>e</u><u>p</u><u>-</u><u>b</u><u>y</u><u>-</u><u>s</u><u>t</u><u>e</u><u>p</u><u> </u><u>e</u><u>x</u><u>p</u><u>l</u><u>a</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u>

We have,

  • The area of rectangular carpet that is 23.4 m²
  • The length of carpet is 13 m.

We know that,

= Area of rectangle = Length × Breadth

= 23.4 = 13 × Breadth

= 23.4/13 = Breadth

= 234/130 = Breadth

= 1.8 m = Breadth

<h2>__________________________</h2>
3 0
2 years ago
There is two questions please help me
pav-90 [236]
36cm
13.6in. my mom helped
3 0
3 years ago
Read 2 more answers
The two-way frequency table shows data on accidents in the last year for drivers who took a driver
Galina-37 [17]

Answer:idk help

Step-by-step explanation:

4 0
2 years ago
What is the equivalent to 28/42
grigory [225]
2/3, since those numbers can be divided by 14.
5 0
3 years ago
2 taps A and B can fill a swimming pool in 3 hours. If turned on alone, it takes tap A 5 hours less than tap B to fill the same
vazorg [7]

Answer:

Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

Step-by-step explanation:

Let tap B fills the pool alone in the time = x hours

So in one hour part of pool will be filled = \frac{1}{x}

Another tap A when turned on, it takes time to fill the pool = x-5 hours

So in one hour part of the same pool filled = \frac{1}{x-5}

Now both the taps A and B are turned on then time taken to fill the pool = 3 hours.

Part of the pool filled in one hour by both the taps = \frac{1}{3}

Now we form an equation

Part of pool filled in one hour by tap A + Part of pool filled in one hour by tap B = Part of pool filled in one hour by both the taps when turned on

\frac{1}{(x-5)}+\frac{1}{x}=\frac{1}{3}

\frac{x-5+1}{x(x-5)}=\frac{1}{3}

\frac{x-4}{x(x-5)}=\frac{1}{3}

3(x - 4) = x(x - 5)

x² -5x = 3x - 12

x² - 8x + 12 = 0

x² - 6x - 2x + 12 = 0

x(x - 6) - 2(x - 6) = 0

(x -2)(x - 6) = 0

x = 2, 6 hours

We will take higher value of x as x = 6 hours for tap B.

Time taken by tap A = 6 - 4 = 2 hours.

Therefore, Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

4 0
3 years ago
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