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dexar [7]
3 years ago
11

Deepak randomly chooses two marbles from the bag, one at a time, and replaces the marble after each choice. What is the probabil

ity he will choose one green marble and then one red marble? Express the probabilities in fraction form.
Mathematics
2 answers:
KIM [24]3 years ago
8 0

it depends how many other colors there are?

Pani-rosa [81]3 years ago
7 0

Answer:

P(green) =  5/14

P(red) =  2/14

P(green and red) =  5/98

Step-by-step explanation:

e2020

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Write a proportion for the statement.<br> 40 is to 10 as 32 is to 8.
Svetach [21]

Hi! ⋇

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  All proportions have <u>this</u> <u>form</u>:

  \sf{\dfrac{a}{b}=\dfrac{c}{d}}, Where \sf{\dfrac{a}{b}} is equal to \sf{\dfrac{c}{d}}.

 If \sf{\dfrac{a}{b}\neq\dfrac{c}{d}}, it's <u>not</u> a proportion.

_________________________

  Here we have two pairs of numbers:

40,10 and 32,8.

Written As a <u>proportion</u>, they <em>look like</em> :

\sf{\dfrac{40}{10}=\dfrac{32}{8}}

Hope this made sense to you :)

\it{Calligrxphy}

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6 0
2 years ago
A high school band director has 120 students in his marching band. The marching band plays at all football games, so the band mu
STatiana [176]
Divide 120 by 2 or divide 120 by 60
3 0
4 years ago
Read 2 more answers
Please help me with this math question
Arturiano [62]

Answer:

145

Step-by-step explanation:

168-23 = 145

    i hope this helps :)

5 0
1 year ago
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The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
(2x+3y+4z)(4x^2+9y^2+16z^2-6xy-12yz-8zx)
erma4kov [3.2K]
1.1 Factoring: 4x2+9y2+16z2-6xy-12yz-8xz

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -6xy-12yz
Group 2: 16z2-8xz
Group 3: 4x2+9y2

Pull out from each group separately :

Group 1: (x+2z) • (-6y)
Group 2: (x-2z) • (-8z)
Group 3: (4x2+9y2) • (1)


Looking for common sub-expressions :

Group 1: (x+2z) • (-6y)
Group 3: (4x2+9y2) • (1)
Group 2: (x-2z) • (-8z)
6 0
3 years ago
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