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Semmy [17]
3 years ago
13

In the Numbers Game, a state lottery, four numbers are drawn with replacement from an urn containing balls numbered 0-9, inclusi

ve. Find the probability that a ticket holder has the indicated winning ticket.
The first two digits in exact order.
Mathematics
1 answer:
Fantom [35]3 years ago
7 0
There are 10 digits from 0 to 9, inclusive.

Thus, number of ways in which four numbers will be drawn from an urn containing balls numbered 0-9, inclusive is given by 10^4=10,000

The number of ways in which a ticket holder will have the first two digits in the correct order is the same as the number of ways in which two numbers will be drawn from the urn containing balls numbered 0-9, inclusive and is given by 10^2=100

Therefore, <span>the probability that a ticket holder has the first two digits in exact order is given by \frac{100}{10,000} = \frac{1}{100} =0.01</span>
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Answer:

Step-by-step explanation:

a.

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

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b.

Population standard deviation is σ = 8.2

<u>So, the standard error of x’ using the finite population correction factor is give by</u>

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

<u>Standard error of x’ without using the finite population correction factor is</u>

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

<u>There is little difference between the two values of the standard error. So we can ignore the population correction factor.</u>

c.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ  + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

<u>So the required probability is </u>

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

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3 years ago
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Just subsitute 8 for n
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7 0
4 years ago
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bezimeni [28]

Answer:

A, B, and C are all true.

Step-by-step explanation:

A. 6 is neither a perfect square nor a perfect cube.   True

B. 16 is a perfect square.   True 4^{2}

C. 27 is a perfect cube.   True 3^{3}

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3 years ago
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141.5 in

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x = (21*10) / 26.25

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