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antoniya [11.8K]

4 years ago

6

A road construction crew is resurfacing the highway between point D and point E. The distance between point D and point E is 93

miles of road. The crew has completed 35 miles. If they work at a pace of 2.9 miles per day, how many more days will it take to finish?

2 answers:

vfiekz [6]4 years ago

4 0

Answer: 20 days.

Step-by-step explanation:

Given: A road construction crew is resurfacing the highway between point D and point E.

The distance between point D and point E =93 miles

Since, the crew has completed 35 miles.

And 90-35=58 miles is the remaining miles of road which crew has to resurface.

If they work at a speed of 2.9 miles per day, then the time it take to finish will be $Time=\frac{Distance}{speed}=\frac{58}{2.9}=20\ days$

Hence, the crew will finish the work in 20 more days.

guajiro [1.7K]4 years ago

3 0

This is my answer. hope it helps! :)

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Please help and thank you

kap26 [50]

Answer:

D is the answer

Step-by-step explanation:

The explenation is shown on the picture above.

5 0

3 years ago

Which expression uses the commutative property to make it easier to evaluate 1/6 • 5/7 • 18?

Korvikt [17]

It’s A, Because if you do KCF (Keep Change Flip) It would be 1/6 X 7/5.

8 0

3 years ago

A type of long-range radio transmits data across the Atlantic Ocean. The number of errors in the transmission during any given a

Marianna [84]

Answer:

32.33% probability of having at least 3 erros in an hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The mean number of errors is 2 per hour.

This means that $\mu = 2$

(a) What is the probability of having at least 3 errors in an hour?

Either you have 2 or less errors in an hour, or we have at least 3 errors. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 2) + P(X \geq 3) = 1$

We want $P(X \geq 3)$

So

$P(X \geq 3) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*(2)^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*(2)^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*(2)^{2}}{(2)!} = 0.2707$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1353 + 0.2707 + 0.2707 = 0.6767$

$P(X \geq 3) = 1 - P(X \leq 2) = 1 - 0.6767 = 0.3233$

32.33% probability of having at least 3 erros in an hour.

6 0

3 years ago

4 to the 3rd power X blank =1 what is the blank?

BaLLatris [955]

If you mean this: $4^{3x} = 1$ then x = 0. The property in play here is the following: Any number raised to the "0" power is equal to "1". In this case, we would need to set the exponent of 3x = 0 and solve for x...

If you mean the equation: $4^{3} x = 1$ then to solve for x(your blank), simply divide both sides of the equation by $4^{3}$ :

You would have x = $\frac{1}{4^3}$ this can also be written as $4^{-3}$

6 0

4 years ago

Which expression is equivalent to (4+3i)^2+(6-I)^2

zhenek [66]

Answer:

$\large\boxed{(4+3i)^2+(6-i)^2=42+12i}$

Step-by-step explanation:

$(4+3i)^2+(6-i)^2\qquad\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2\\\\=4^2+2(4)(3i)+(3i)^2+6^2-2(6)(i)+i^2\\\\=16+24i+9i^2+36-12i+i^2\qquad i=\sqrt{-1}\to i^2=-1\\\\=16+24i+9(-1)+36-12i+(-1)\\\\=16+24i-9+36-12i-1\qquad\text{combine like terms}\\\\=(16-9+36-1)+(24i-12i)\\\\=42+12i$

8 0

4 years ago