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Zigmanuir [339]
4 years ago
5

Divide 300 g^2 0.0005 g and express using scientific notation

Mathematics
2 answers:
VladimirAG [237]4 years ago
4 0

Answer:

\Rightarrow 6\times 10^5\ g

Step-by-step explanation:

Given : Divide two number and write as scientific notation.

Scientific notation:

\Rightarrow k\times 10^n

Number 1: 300 g²

Number 2: 0.0005 g

Divide =\dfrac{300\ g^2}{0.0005\ g}

\Rightarrow \dfrac{30\times 10}{5\times 10^{-4}\ g{2-1}

\Rightarrow 6\times 10^{1+4}\ g

\Rightarrow 6\times 10^5\ g

Scientific notation:

\Rightarrow k\times 10^n

Hence, The result of division is \Rightarrow 6\times 10^5\ g

pickupchik [31]4 years ago
3 0
(300g^2) / (0.0005g) = 600,000g = 6 x 10^5g
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Find a solution to the initial value problem, y′′+18x=0,y(0)=5,y′(0)=1.
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We want to find a solution to the initial value problem:

y'' + 18x = 0 \qquad,\qquad y(0) = 5 \qquad,\qquad y'(0)=1.

We can start by integrating the equation once:

\dfrac{\textrm{d}^2 y}{\textrm{d}x^2} + 18 x = 0 \iff \dfrac{\textrm{d}^2 y}{\textrm{d}x^2} = -18 x \iff\\\\\iff \dfrac{\textrm{d}y}{\textrm{d}x} = -18\displaystyle\int x\textrm{ d}x \iff \dfrac{\textrm{d}y}{\textrm{d}x}=-18\dfrac{x^2}{2} + C \iff\\\\\iff \dfrac{\textrm{d}y}{\textrm{d}x} = -9x^2 + C.

Using the initial condition y'(0) = 1, we can determine the integration constant C:

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Therefore, we have:

\dfrac{\textrm{d}y}{\textrm{d}x} = -9x^2 + 1

We can now integrate again:

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There are 11 more goats than sheep in the farm. Together there are 137 animals in the farm. How many goats and how many sheep ar
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Answer:

The number of goats in the farm is 74

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Step-by-step explanation:

Let

x----> the number of goats in the farm

y----> the number of sheep    

we know that

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x=y+11 -----> equation B

substitute the equation B in equation A and solve for y

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The number of sheep in the farm is 63

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