Written in standard form, the hyperbola's equation is ...
... y^2/7 - x^2/28 = 1
Then the ends of the transverse axis are located at y = ±√7. The region between these values is excluded from the range of the relation.
Answer:
15%
Step-by-step explanation:
The tank's capacity is 200,000 gallons.
170,000 gallons were used.
200,000 - 170,000 = 30,000
30,000 gallons of fuel are still there.
percent = part/total * 100%
percent = 30,000/200,000 * 100% = 15%
z = -5
3(0.7z + 2.8) = 7(1.5z + 7.2)
2.1z + 8.4 = 10.5z + 50.4
2.1z - 10.5z = 50.4 - 8.4
-8.4z = 42
z = 42/(-8.4)
Answer: the answers are 10(x+15)+20(x+30) and 10x+150+20x+600 and 30x+750
63.5
9.3(3)+8.9(4) = 63.5
substitute the values (s and t) with the given numbers (3 and 4.)
2A / r^2 = pi
A = 1/2 pi r^2
Multiply by 2
2A = pi r^2
Divide by r^2
2A / r^2 = pi r^2/r^2
