Question

Jennifer went to the post office for stamps. She bought the same number of 8-cent stamps and 10-cent stamps. She also bought as many 2-cent stamps as both of the other two kinds combined. How many of each kind did she get if she paid a total of $4.40 for them all?

Answer 1

E=number of eight cent stamps
t=number of ten cent stamps bought
w=number of 2 cent stamps bought

number of eight=number of ten
e=t

as many 2 cent as the other 2 combined
e+t=w or
2e=w=2t

total she bouthgt 4.40
4.40=440 cents
8e+10t+2w=440
solve for t or e, I solve for t
8t+10t+2(2t)=440
18t+4t=440
22t=440
divide 22
t=20


t=e
20=e
w=2e
w=2(20)
w=40


answer is
20 eight cent
20 ten cent
40 two cent