Question

A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 n/m. at t=0 the block has velocity -4.00 m/s and displacement +0.200 m. write an equation for the position as a function of time.

Answer 1

So we need to acknowledge that we are integrating with respect to common sense. The integral of velocity will give us the position function. $v = \frac{ds}{dt}= \mathrm{common\ sense} \\ ds = \mathrm{common\ sense} \ dt \\ \int ds = \int \mathrm{common\ sense} \ dt \\ s = \mathrm{common\ sense} (t) + C$

Go post this in physics lol