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kakasveta [241]
3 years ago
9

H(t)=(t+3)^2+5 Over which interval does h have a negative average rate of change?

Mathematics
2 answers:
VikaD [51]3 years ago
6 0

Answer: -4<t<-3

Step-by-step explanation:

Yuri [45]3 years ago
4 0

Answer:

( -∞, -3 ) or any subinterval of  ( -∞, -3 )

Step-by-step explanation:

h(t)=(t+3)^2+5 has the form

h(t) =(t-h)^2 + 5, indicating that h(t)=(t+3)^2+5 represents a parabola with vertex at (-3,5) that opens up.  This (-3,5) is the minimum point of the graph.

To the left of t = -3, h(t) is decreasing; to the right of t = -3, h(t) is increasing.

Thus, it is on any interval to the left of t = -3 that the rate of change of this function is negative (the function is decreasing  on ( -∞, -3 ).

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A soft drink machine outputs a mean of 27 ounces per cup. The machine's output is normally distributed with a standard deviation
postnew [5]

Answer: P(22 ≤ x ≤ 29) = 0.703

Step-by-step explanation:

Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

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From the information given,

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Looking at the normal distribution table, the probability corresponding to the z score is 0.047

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6 0
3 years ago
What is the slope <br> y = (34/4)x + 3
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Answer:

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