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Whitepunk [10]
3 years ago
7

Help with Trig please.

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

60 units

Step-by-step explanation:

Ratio of the perimeter = ratio of sides

Sides are in the ratio:

6 : 24

1 : 4

Perimeter of the first triangle:

4+5+6 = 15

Perimeter of the second triangle:

4(15) = 60

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43°24' = 43° + 24'/60 = 43.4°

putting <span> sin(43.4)</span>into calculator to  8 decimal places

sin(43°24') = sin(43.4) = 0.68708751




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4 years ago
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Brian ate 3 granola bars. This is 25% of the total number of granola bars I'm a box. How many granola bars are in a box.
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75% is left in the box
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Step-by-step explanation:

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3 years ago
The width of a rectangle is 7t-4.5 feet and the length is 4.5t+9 feet. Find the perimeter of the
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6 0
3 years ago
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
3 years ago
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