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algol [13]
4 years ago
12

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
1 answer:
Law Incorporation [45]4 years ago
5 0

x^3-8x^2-x+8=0\\\\x^2(x-8)-1(x-8)=0\\\\(x-8)(x^2-1)=0\iff x-8=0\ \vee\ x^2-1=0\\\\x-8=0\ \ \ |+8\\x=8\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt1\to x=\pm1\\\\Answer:\ x=-1\ or\ x=1\ or\ x=8

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Part A:

If (7^2)^x = 1 then the value of x is equal 0

Because when x = 0 the

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if x = 1000 then (7^0)^(1000) = 7^0 = 1

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