Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

$x^3-8x^2-x+8=0\\\\x^2(x-8)-1(x-8)=0\\\\(x-8)(x^2-1)=0\iff x-8=0\ \vee\ x^2-1=0\\\\x-8=0\ \ \ |+8\\x=8\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt1\to x=\pm1\\\\Answer:\ x=-1\ or\ x=1\ or\ x=8$