What are the roots of the polynomial equation 3x^4+12x^2=6x^3
1 answer:
Factor the equation to give
By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 ± √ (3) i
Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+√3 i, 1-√3 i}</span>
By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 ± √ (3) i
Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+√3 i, 1-√3 i}</span>
You might be interested in
Answer:
The correct option is (D).
Step-by-step explanation:
It is given that GIKMPR is regular hexagon. It means it has 6 vertices.
Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is
It is given that the dashed line segments form 30 degree angles.
We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.
The vertex R is immediate next to the vertex P in clockwise direction.
So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.
Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.
Therefore option D is correct.
